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discordf
Centipat
- Katılım
- 1 Nisan 2023
- Mesajlar
- 768
- Çözümler
- 8
adım 1: önce 2 sayısını kesir olarak ifade edelim:
2 = 422 = \frac{4}{2}2 = 24.
adım 2: diğer 2'yi de kesir olarak yazalım:
2 = 842 = \frac{8}{4}2 = 48.
adım 3: şimdi bu iki kesiri toplayalım. Önce paydaları eşitleyelim:
42+84=84+84=168\frac{4}{2} + \frac{8}{4} = \frac{8}{4} + \frac{8}{4} = \frac{16}{8}24+48 = 48+48 = 816.
Burada:
2+2 = 168 = 2×44 = 84×4 = 8162 + 2 = \frac{16}{8} = 2 \times \frac{4}{4} = \frac{8}{4 \times 4} = \frac{8}{16}2+2 = 816 = 2×44 = 4×48 = 168.
adım 4: kesiri biraz daha düzenleyelim:
168=2\frac{16}{8} = 2816 = 2
adım 5: şimdi 4'ü çarpanlarına ayıralım:
4 = 2×2=(2×2)×(2×2)=2×2×2×24 = 2 \times 2 = (2 \times 2) \times (2 \times 2) = 2 \times 2 \times 2 \times 24 = 2×2=(2×2)×(2×2)=2×2×2×2
adım 6: Pi sayısına yaklaşmaya çalışalım. Pi'yi içeren bir denklem kullanalım:
4π×π=4\frac{4}{\pi} \times \pi = 4Π4×π = 4
Pi'nin serisiyle ilişkilendirelim:
2+2 = 42 + 2 = 42+2 = 4
Ve Pi'nin uzun haliyle sonuçlandıralım:
π≈3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337867831652712019091456485669234603486104543266482133936072602491412737245870066063155881748815209209628292540917153643678925903600113305305488204665213841469519415116094330572703657595919530921861173819326117931051185480744623799627495673518857527248912279381830119491\pi \approx 3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337867831652712019091456485669234603486104543266482133936072602491412737245870066063155881748815209209628292540917153643678925903600113305305488204665213841469519415116094330572703657595919530921861173819326117931051185480744623799627495673518857527248912279381830119491π≈3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337867831652712019091456485669234603486104543266482133936072602491412737245870066063155881748815209209628292540917153643678925903600113305305488204665213841469519415116094330572703657595919530921861173819326117931051185480744623799627495673518857527248912279381830119491
sonuç: sonuç olarak:
2+2≈3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706798214808651328230664709384460955058223172535940812848111745028410270193852110555964462294895493038196442881097566593344612847564823378678316527120190914564856692346034861045432664821339360726024914127372458700660631558817488152092096282925409171536436789259036001133053054882046652138414695194151160943305727036575959195309218611738193261179310511854807446237996274956735188575272489122793818301194912 + 2 \approx 3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706798214808651328230664709384460955058223172535940812848111745028410270193852110555964462294895493038196442881097566593344612847564823378678316527120190914564856692346034861045432664821339360726024914127372458700660631558817488152092096282925409171536436789259036001133053054882046652138414695194151160943305727036575959195309218611738193261179310511854807446237996274956735188575272489122793818301194912+2≈3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337867831652712019091456485669234603486104543266482133936072602491412737245870066063155881748815209209628292540917153643678925903600113305305488204665213841469519415116094330572703657595919530921861173819326117931051185480744623799627495673518857527248912279381830119491
Hocam sorunun cevabı hâlâ bulunamadı, belki bir umut.
